No Fermat pseudoprime of the form u²−2 to base 2
THE PRIME NUMBER SERIES 31
No Fermat pseudoprime of the form u²−2 to base 2
**Theorem.**
There exists no composite odd number
![]()
for which
![]()
holds.
—
**Proof.**
We carry out the proof by contradiction.
Assume that there exists a composite odd number
![]()
with
![]()
Then U is a Fermat pseudoprime to base 2.
For every prime divisor p ∣ U we have
(1) ![]()
From
follows
![]()
thus
thus is a quadratic residue modulo
. Thus it holds
![]()
and by the law of quadratic reciprocity
(2) ![]()
Since u is odd, we have
, therefore
![]()
In particular
is odd.
Because
is a square modulo
, follows
(3) ![]()
From (1) and (3) we obtain
(4) ![]()
**Lemma.** For every prime divisor
we have
![]()
*Proof of the Lemma.*
From
exists a
with
![]()
thus
![]()
Let
![]()
Then we have
![]()
From
follows
(5) ![]()
Reduction of
modulo
yields, because of (5)
(6) ![]()
On the other hand, it follows from ![]()
(7) ![]()
From (6) and (7) follows
![]()
Thus it holds
![]()
Because
, follows
.
Because
is odd, it follows
![]()
thus
.
—
From (4) and the lemma it follows
![]()
thus
![]()
which is impossible for a prime number p>1.
The contradiction shows that the assumption was false.
Thus there exists no composite odd number of the form
![]()
that is a Fermat pseudoprime to base 2.
Munich, 11 January 2026
Gottfried Färberböck
Archived version:
G. Färberböck, “No Fermat pseudoprime of the form u²−2 to base 2”,
Zenodo (2026).
https://doi.org/10.5281/zenodo.18232110

